Question

Factorise: a3 - 4a2 + 12​

Answer 1

Answer:

$\large {\boxed {\fcolorbox {aqua} {green} {A = 4}}}$

Step-by-step explanation:

$\large {\boxed {\fcolorbox {red} {aqua} {Answer}}}$

$= > {a}^{3} - 4 {a}^{2} + 12 \\ = > {a}^{2}(a - 4) + 12 \\ = > a = 4$

Answer 2

Answer:

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Step-by-step explanation:

$a^{3}-4a^{2}+12-3a\\\\(a^{3}-4a^2)-(3a-12)\\\\a^2(a-4)-3(a-4)\\\\ [(a-4)(a^2-(\sqrt{3})^2 )} \\\\use\: a^2-b^2=(a+b)(a-b), we\:get\\\\(a-4)(a-\sqrt{3} )(a+\sqrt{3} )$