factorise a³-4b³-64c³-12²abc
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Answered by
0
Let's simplify step-by-step.
a3−4b3−64c3−(122)(a)bc
=a3+−4b3+−64c3+−144abc
Answered by
1
Answer:
hope this helps you
Step-by-step explanation:
answer is a3 -48a+8a2
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