Question

factorise a3+8b3+12ab2+6a2b​

Answer 1

Answer:

Changes made to your input should not affect the solution:

 (1): "b3"   was replaced by   "b^3".  3 more similar replacement(s).

STEP1:Equation at the end of step 1

(((a3)+((6•(a2))•b))+(12a•(b2)))+23b3

STEP 2 :

Equation at the end of step2:

(((a3)+((6•(a2))•b))+(22•3ab2))+23b3

STEP 3 :

Equation at the end of step3:

(((a3) + ((2•3a2) • b)) + (22•3ab2)) + 23b3

STEP4:Checking for a perfect cube

 4.1    Factoring:  a3+6a2b+12ab2+8b3  

 .

  a3+6a2b+12ab2+8b3  is a perfect cube which means it is the cube of another polynomial 

 In our case, the cubic root of  a3+6a2b+12ab2+8b3  is  a+2b  

 Factorization is  (a+2b)3

Final result :

(a + 2b)3

Step-by-step explanation:

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Answer 2

a+a+a+8×3+12×2+6×2

a3+24+24+12

and

564 is your answer

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