factorise a3+8b3+12ab2+6a2b
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Answered by
0
Answer:
Changes made to your input should not affect the solution:
(1): "b3" was replaced by "b^3". 3 more similar replacement(s).
STEP1:Equation at the end of step 1
(((a3)+((6•(a2))•b))+(12a•(b2)))+23b3
STEP 2 :
Equation at the end of step2:
(((a3)+((6•(a2))•b))+(22•3ab2))+23b3
STEP 3 :
Equation at the end of step3:
(((a3) + ((2•3a2) • b)) + (22•3ab2)) + 23b3
STEP4:Checking for a perfect cube
4.1 Factoring: a3+6a2b+12ab2+8b3
.
a3+6a2b+12ab2+8b3 is a perfect cube which means it is the cube of another polynomial
In our case, the cubic root of a3+6a2b+12ab2+8b3 is a+2b
Factorization is (a+2b)3
Final result :
(a + 2b)3
Step-by-step explanation:
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Answered by
9
a+a+a+8×3+12×2+6×2
a3+24+24+12
and
564 is your answer
hope it helps you❤
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