factorise a3+8b3+27c3-18abc
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Step-by-step explanation:
a³+8b³+27c³-18abc
=a³+(2b)³+(3c)³-3(a)(2b)(3c)
=(a+2b+3c) { a²+(2b)²+(3c)² -a(2b)-(2b)(3c)-(3c)(a) }
=(a+2b+3c) ( a²+4b²+9c² -2ab-6bc-3ca)
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here is your answer have a great day
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