Question

factorise: a³+8b³-c³+6abc​

Answer 1

Step-by-step explanation:

a^3+8b^3-c^3+6abc

=(a+2b -c)(a^2+4b^2+c^2-2ab +2bc +ca)

Answer 2

Step-by-step explanation:

=a^3+(2b)^3+(-c)^3-3*a*2b*(-c)=(a+2b-c)[a^2+(2b)^2+(-c)^2-a*2b-2b*(-c)-a*(-c)]=(a+2b-c)(a^2+4b^2+c^2-2ab+2bc+ac)