Factorise a³(b-c)³+b³(c-a)³+c³(a-b)³
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a³(b-c)³+b³(c-a)³+c³(a-b)³
Let x = a(b-c) , y = b(c-a), z = c(a-b)
Here , x + y + z = 0
Then x³ + y³ + z³ must be equal to 3xyz.
Substitute for x = a(b-c) , y = b(c-a), z = c(a-b) and get the answer.
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