Question

factorise a³-b³+1+3ab​

Answer 1

Answer:

Step-by-step explanation:

$x^{3} +y^{3}+z^{3}-3xyz=(x+y+z)(x^{2}+y^{2} + z^{2} -xy-yz-xz)\\therefore\\\a^{3} -b^{3}+1+3ab=a^{3} +-(b)^{3}+1^{3}-3a*(-b)*1=(a-b+1)(a^{2} +b^{2} +1+ab-a+b)$

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