factorise a3-b3+1+3ab
Answers
Answered by
65
As we know,
a³+b³+c³-3abc = (a+b+c)(a²+b²+c²-ab-bc-ca)
here c= -1
→ a³-b³+1+3ab
a³+b³+c³-3abc = (a+b+c)(a²+b²+c²-ab-bc-ca)
here c= -1
→ a³-b³+1+3ab
Answered by
3
Answer:
Step-by-step explanationa³+b³+c³-3abc = (a+b+c)(a²+b²+c²-ab-bc-ca)
here c= -1
→ a³-b³+1+3ab
:
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