Factorise: a³-b³+1+3ab
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a^3-b^3+1+3ab
=a^3+(-b)^3+1^3-3(1*a*(b))
={a+(-b)+1){a^2+(-b)^2+1^2-a(-b)-(-b) 1-1a}
=(a-b+1)(a^2+b^2+1+ab+b-a)
=a^3+(-b)^3+1^3-3(1*a*(b))
={a+(-b)+1){a^2+(-b)^2+1^2-a(-b)-(-b) 1-1a}
=(a-b+1)(a^2+b^2+1+ab+b-a)
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