Question

Factorise a3+b3+3ab-1

Answer 1

As we know that

x3+y3+z3-3xyz=(x+y+z)(x2+y2+z2-xy-yz-zx)

In your question let

x=a

y=b

& z= -1

Now putting the values in above formula

a3+b3+(-1)3-3ab(-1)=(a+b+(-1))(a2+b2+(-1)2-ab-b(-1)-(-1)a)

a3+b3-1+3ab = (a+b-1)(a2+b2+1-ab+b+a)

So your answer is

(a+b-1)(a2+b2-ab+a+b+1)

If you like it hit thanks

Answer 2

Answer:

cannot be factorised i guess

Step-by-step explanation: