factorise a³ + b³ + 8c³- 6abc
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(a + b + 2c)² - 2ab - 4ac - 4bc
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Answered by
5
given a³ + b³ + 8c³- 6abc
so using formula of (a + b + c)²
(a + b + 2c)² - 2ab - 4ac - 4bc
so using formula of (a + b + c)²
(a + b + 2c)² - 2ab - 4ac - 4bc
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