factorise a³-b³-a(a²-b²)+b(a-b)²
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Step-by-step explanation:
Given that:-
a³-b³-a(a²-b²)+b(a-b)²
=>(a-b)(a²+ab+b²)-a(a+b)(a-b)+b(a-b)(a-b)
=>(a-b)[(a²+ab+b²)-a(a+b)+b(a-b)]
=>(a-b)[a²+ab+b²-a²-ab+ab-b²]
=>(a-b)(ab)
a³-b³-a(a²-b²)+b(a-b)²=(a-b)(ab)
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