Factorise a³ + b³ + c³
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a3 + b3 + c3 - 3abc = (a + b + c)(a2 + b2 + c2 - ab - bc - ca) is the answer bro
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Your answer is
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a3 + b3 + c3 - 3abc = (a + b + c)(a2 + b2 + c2 - ab - bc - ca)
Hope it helps Mark as brainliest
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___________________________
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a3 + b3 + c3 - 3abc = (a + b + c)(a2 + b2 + c2 - ab - bc - ca)
Hope it helps Mark as brainliest
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