Question

Factorise a³ + b³ + c³ - 3abc.

Answer 1

Hi there!

We know the following Identity :
x³ + y³ + z³ - 3xyz = ( x + y + z) ( x² + y² + z² - xy - yz - zx )

Here ,

x = a
y = b
z = c

Then,
(a)³ + (b)³ + (c)³ - 3abc = ( a - b - c) [ a² + b² + c² + ab - bc + ca ]

Hope it helps! :D

Answer 2

hey!!

here is your answer...! =>

$a^{3} + b^{3} + c^{3} - 3abc = (a + b + c)(a2 + b2 + c2 - ab - bc - ca)$

hope this helps!