Question

factorise : a³b³-3√3c³​

Answer 1

Answer:

A³+3√3b³

⇒(a)³+(√3b)³

⇒(a)³+(√3b)³=(a+√3b){(a²)-a*√3b+(√3b)²}

=(a+√3b)(a²-√3ab+3b²)

Step-by-step explanation: