Question

factorise a3x3-3a2bx2+3ab2x-b3
please solve if you can

Answer 1

${a}^{3} {x}^{3} - 3 {a}^{2} b {x}^{2} + 3a {b}^{2} x - {b}^{3 } \\ compare \: this \: expression \: with \: the \: identity \\ ( {x - y)}^{3} = {x}^{3} - 3 {x}^{2} y + 3x {y}^{2} - {y}^{3} \\ so \\ ( {ax)}^{3} - 3( {ax)}^{2} y + 3ax {y}^{2} - ( {y)}^{3} \\ = ( {ax - b)}^{3} \\ so \: factors \: are \: (ax - b)(ax - b)(ax - b)$

Answer 2

Answer: Here is the answer:-(ax-b)(ax-b)(ax-b)