Question

Factorise: a6 -7a3-8

Answer 1

Answer:(a+1)(a-2)(a^2 - a + 1)(a^2 + 2a +4)

Step-by-step explanation:

Let a^3 = x

Therefore the equation becomes,

x^2 - 7x - 8

= x^2 - 8x + x - 8

= x(x-8) + 1(x-8)

= (x+1)(x-8)

Putting the value of x

(a^3 + 1)(a^3 - 8)

Application of formulas -

1. (A^3 + B^3) = (A + B)(A^2 + B^2 - AB)

2. (A^3 - B^3) = (A - B)(A^2 + B^2 + AB)

We get,

={(a+1)(a^2 + 1 - a)}{(a-2)(a^2 + 4 + 2a)}

Simplifying it,

=(a+1)(a-2)(a^2 - a +1)(a^2 + 2a + 4)

This is the final answer.

Plz mark as the brainliest answer!!

Answer 2

thanks for asking the question

the answer is in pic