factorise : ab^2-(a-b)b-c ?
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➡a²- b² + ac - bc
➡Identity used :-
↪(a + b)² =a² + b² + 2ab
➡= (a² - b²) + (ac - bc)
➡= (a + b)x(a - b) + c(a - b)
➡= (a - b)x[(a + b) + c]
➡= (a - b)x(a + b + c) is the required answer
➡a²- b² + ac - bc
➡Identity used :-
↪(a + b)² =a² + b² + 2ab
➡= (a² - b²) + (ac - bc)
➡= (a + b)x(a - b) + c(a - b)
➡= (a - b)x[(a + b) + c]
➡= (a - b)x(a + b + c) is the required answer
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