factorise ab^2-ac^2
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a(b+c)(b-c)
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On factoring ab²- ac² we will get a (b-c) (b+c)
Given:
ab²- ac²
To find:
Factorise ab²- ac²
Solution:
Given ab²- ac²
Take a common
⇒ a (b² - c²)
From algebraic identities,
(a² - b²) = (a + b) (a - b)
Take a = b and b = c and apply above formula
(b² - c²) = (b - c) (b + c)
⇒ a (b² - c²) = a [ (b - c) (b + c)]
= a (b-c) (b+c)
Therefore,
On factoring ab²- ac² we will get [ a(b-c) (b+c) ]
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