Question

factorise ab-ac-mb+mc​

Answer 1

Answer:

$\mathcal {= (a - m) (b - c) }$

Step-by-step explanation:

= ab - ac - mb + mc

$\mathbb{TAKING \: \: COMMON \: \: OUT, }$

= a(b - c ) - m(b - c)

= (a - m) (b - c)