Question

factorise = ab(c^2+d^2)-a^2cd-b^2cd​

Answer 1

Step-by-step explanation:

Given, (d

Given, (d 2

Given, (d 2 +c

Given, (d 2 +c 2

Given, (d 2 +c 2 )ab−a

Given, (d 2 +c 2 )ab−a 2

Given, (d 2 +c 2 )ab−a 2 cd−b

Given, (d 2 +c 2 )ab−a 2 cd−b 2

Given, (d 2 +c 2 )ab−a 2 cd−b 2 cd,

Given, (d 2 +c 2 )ab−a 2 cd−b 2 cd,=abd

Given, (d 2 +c 2 )ab−a 2 cd−b 2 cd,=abd 2

Given, (d 2 +c 2 )ab−a 2 cd−b 2 cd,=abd 2 +abc

Given, (d 2 +c 2 )ab−a 2 cd−b 2 cd,=abd 2 +abc 2

Given, (d 2 +c 2 )ab−a 2 cd−b 2 cd,=abd 2 +abc 2 −cda

Given, (d 2 +c 2 )ab−a 2 cd−b 2 cd,=abd 2 +abc 2 −cda 2

Given, (d 2 +c 2 )ab−a 2 cd−b 2 cd,=abd 2 +abc 2 −cda 2 −cdb

Given, (d 2 +c 2 )ab−a 2 cd−b 2 cd,=abd 2 +abc 2 −cda 2 −cdb 2

Given, (d 2 +c 2 )ab−a 2 cd−b 2 cd,=abd 2 +abc 2 −cda 2 −cdb 2 ,

Given, (d 2 +c 2 )ab−a 2 cd−b 2 cd,=abd 2 +abc 2 −cda 2 −cdb 2 ,

Given, (d 2 +c 2 )ab−a 2 cd−b 2 cd,=abd 2 +abc 2 −cda 2 −cdb 2 , rearrange and,

Given, (d 2 +c 2 )ab−a 2 cd−b 2 cd,=abd 2 +abc 2 −cda 2 −cdb 2 , rearrange and,=bc(ac−bd)−ad(ac−bd)

Given, (d 2 +c 2 )ab−a 2 cd−b 2 cd,=abd 2 +abc 2 −cda 2 −cdb 2 , rearrange and,=bc(ac−bd)−ad(ac−bd)=(ac−bd)(bc−ad)