factorise ab(x²+y²)-xy(a²+b²)
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Answered by
10
Answer:=(bx-ay)(ax-by)
Step-by-step explanation:
=abx²+aby²-a²xy-b²xy
=abx²-a²xy + aby² - b²xy
=ax(bx-ay) - by( -ay + bx)
=axbx-axay+byay-bybx
=(bx-ay)(ax-by)
Answered by
6
step by step explanations: abx2+aby2-a2xy+b2xy
abx2-a2xy-b2xy+aby2
ax(bx-ay)-by(bx-ay)
(bx-ay) (ax-by)
abx2-a2xy-b2xy+aby2
ax(bx-ay)-by(bx-ay)
(bx-ay) (ax-by)
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