Factorise ab2+(a-1)b-1
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Answered by
322
Hi,
ab^2 + ( a - 1 ) b - 1
= ab^2 + ab - b - 1 [ using distributing property ]
= ab ( b + 1 ) - 1 ( b + 1 )
Take ( b + 1 ) is as common factor
= ( b + 1 ) ( ab - 1 )
Therefore,
( b + 1 ) , ( ab - 1 ) are two factors.
I hope this helps you.
:)
ab^2 + ( a - 1 ) b - 1
= ab^2 + ab - b - 1 [ using distributing property ]
= ab ( b + 1 ) - 1 ( b + 1 )
Take ( b + 1 ) is as common factor
= ( b + 1 ) ( ab - 1 )
Therefore,
( b + 1 ) , ( ab - 1 ) are two factors.
I hope this helps you.
:)
Answered by
76
ab²+ab–b–1
an(b+1)–1(b+1)
(b+1) (ab–1)
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