Question

factorise ab²-bc²-ab+c²

Answer 1

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Here is u r Ans ➡

✨
$= ab {}^{2} - bc {}^{2} - ab + c {}^{2}$

$= b \times (ab - c {}^{2} ) - ab + c {}^{2}$

$= b \times (ab - c {}^{2} ) - (ab - c {}^{2} )$

$= (ab - c {}^{2} )(b - 1)$
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Answer 2

$\huge{\underline{\tt{QUESTION:-}}} \\ \\ Factorise \: the following \: - \\ \\ a {b}^{2} - b {c}^{2} - ab + {c}^{2} \\ \\ \huge{\underline{\tt{ANSWER:-}}} \\ \\ a {b}^{2} - b {c}^{2} - ab + {c}^{2} \\ = b(ab - {c}^{2} ) - ab + {c}^{2} \\ = b(ab - {c}^{2} ) - 1(ab - {c}^{2} ) \\ = (ab - {c}^{2} )(b - 1)$