factorise above question
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Step-by-step explanation:
2√2a³+8b³-27c³+18√2abc
=>(√2a)³+(2b)³+(-3c)³-3(√2a)(2b)(-3c)
=>(√2a+2b-3c)(2a²+4b²+9c²-2√2ab+6bc+3√2ca)
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