Factorise acx power 2 +bcx-adx-bd
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Answered by
48
Answer:
acx² - (ad + bc)x + bd
= acx² - adx - bcx + bd
= ax(cx - d) - b(cx - d)
= (ax - b)(cx - d)
hope this helps you
Anant124:
can you folow me
Answered by
138
acx² - (ad + bc)x + bd
= acx² - adx - bcx + bd
= ax(cx - d) - b(cx - d)
= (ax - b)(cx - d)
Answered by
148
acx² - (ad + bc)x + bd
= acx² - adx - bcx + bd
= ax(cx - d) - b(cx - d)
= (ax - b)(cx - d)
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