Question

factorise algebraic 1/8a³+8/b³​

Answer 1

Given: The term 1/8a³+8/b³​

To find: Factorise the given equation.

Solution:

• Now we have given the term:

                     1/8a³+8/b³​

• We can rewrite it as:

                     (1/2a)³ + (2/b)³​

• Now we know the formula:

                     a³ + b³ = (a + b)(a² - ab + b²)

• Applying this, we get:

                     (1/2a)³ + (2/b)³​ = (1/2a + 2/b)( (1/2a)² - (1/2a)(2/b) + (2/b)² )

                     (1/2a)³ + (2/b)³​ = (1/2a + 2/b)( 1/4a² - 1/ab + 4/b² )

                         

Answer:

                  So the factors are (1/2a + 2/b)( 1/4a² - 1/ab + 4/b² )

Answer 2

Answer:

thank you it's very help full mate thanks alot