Question

Factorise (Algebraic Identities )

64a square +49b square + 112 ab

Answer 1

Hey friend your answer is here

64a + 49b + 112ab

= (8a)² + (7b)² + 2(8a)(7b)

As we know

A² + B² + 2AB = (A + B)²

So,

64a + 49b + 112ab = (8a + 7b)²

= (8a + 7b) (8a + 7b)

Hope it will be helpful to you

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