Math, asked by kaustubhshingate, 8 months ago

factorise and divide:- 15(y-3)(y^2 - 16) / 5(y^2-y-12)

Answers

Answered by pansumantarkm
4

Step-by-step explanation:

 \frac{15(y - 3)( {y}^{2} - 16) }{5( {y}^{2} - y - 12) }  \\  \\  =  \frac{15(y - 3)(( {y)}^{2} -  {(4)}^{2} ) }{5( {y}^{2} - 4y + 3y - 12) }  \\  \\  =  \frac{15(y - 3)(y + 4)(y - 4)}{5(y(y  -  4) + 3(y - 4))}  \\  \\  =  \frac{15(y - 3)(y + 4)(y - 4)}{5(y  - 4)(y + 3)}  \\  \\  =  \frac{3(y - 3)(y + 4)}{(y + 3)}

Concept Used:

  • - = (a + b)(a - b)
  • Middle term factorization

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