Factorise and divide the following expressions:
a) 26xy(xy+5y-4x-20)÷104(xy-4x)
b) 14xy(25x²-16y²)÷6xy(5x+4y)
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Answer:
={(x2 + 3y2 - 6xy) + (2x2 - y2 + 8xy) + ( y2 + 8) + (x2 - 3xy)} ... We have. P + Q + R = (7x2 + 5xy - 9y2) + (4y2 - 3x2 - 6xy) + (- 4x2 + xy + 5y2) ... 20 - [5xy + 3{x2 - xy + 2y - x}] ... 85 + 104x - 41
Step-by-step explanation:
Systems of equations with elimination: 6x-6y=-24 & -5x-5y=-60 ... Systems of equations with substitution: 2y=x+7 & x=y-4.
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