Question

Factorise and divide the given expressions :
$18y^{3} (8y^{2} -18)$÷$9y^{2}(2y+3)$
Please only answer if you know how to solve it. Not applicable answers will be reported.

Answer 1

$\frac{18 {y}^{3} (8 {y}^{2} - 18)}{9 {y}^{2}(2y + 3) } \\ = \frac{9 \times {y}^{2} \times y \times2 (4 {y}^{2} - 9 )}{9 \times {y}^{2} \times (2y + 3) } \\ = 2y \times \frac{( {(2y)}^{2} - {(3)}^{2} )}{(2y + 3)} \\ = 2y \times \frac{(2y - 3)(2y + 3)}{(2y + 3)} \\ = 2y \times (2y - 3) \\ = 2y(2y - 3)$