Math, asked by Anonymous, 6 months ago

factorise and find roots
2 {x}^{2}  - x + 1 = 0

Answers

Answered by Anonymous
13

\green{\bold{\underline{ ✪ UPSC-ASPIRANT✪ }}}

\red{\bold{\underline{\underline{QUESTION:-}}}}

Q:-factorise and find roots

2 {x}^{2} - x + 1 = 0

\huge\tt\underline\blue{Answer }

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⟹</p><p>2 {x}^{2}  - x + 1 = 0

⟹</p><p>2 {x}^{2}  - 2x + x + 1 = 0

⟹</p><p>2x(x - 1) - 1(x - 1) = 0

⟹</p><p>(2x - 1)(x - 1) = 0

⟹</p><p>2x - 1 = 0

⟹</p><p>x =  \frac{1}{2}

⟹</p><p>x - 1 = 0

⟹</p><p>x = 1

HOPE IT HELPS YOU..

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Answered by EthicalElite
30

 \sf \huge \orange {Answer}

 \sf 2{x}^{2} - x + 1 = 0

 \sf  2{x}^{2} - 2x + x + 1 = 0

 \sf  2x(x - 1) - 1(x - 1) = 0

 \sf  (2x - 1)(x - 1) = 0

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 \sf 2x - 1 = 0

 \boxed {\sf x = \frac{1}{2}}

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 \sf  x - 1 = 0

 \boxed{\sf  x = 1}

 \sf \red {Therefore, \: value \: of \: x = \frac{1}{2} \: and \: x=1}

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