Question

factorise and find the roots of 7×2+13×-2=0​

Answer 1

ANSWER✔

$\implies 7x^2+13x-2=0$

$\implies 7x^2+14x-x-2=0$

$\implies 7x(x+2)-1(x+2)=0$

$\implies (7x-1)(x+2)=0$

$\implies 7x-1=0, x+2=0$

$\implies x= \dfrac{1}{7}, x= -2$

$\implies x= \dfrac{1}{7},-2$

$\large{\boxed{\bf{ \star\:\: the\:roots\:of\:7x^2+13x-2\:are\: \dfrac{1}{7}\:and\:-2.\:\: \star}}}$

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Answer 2

Answer:

✡ Question ✡

$\leadsto$ 7x² + 13x - 2 = 0

$\implies$ 7x² + (14-1)x - 2 = 0

$\implies$ 7x² + 14x - x - 2 = 0

$\implies$ 7x (x + 2) - 1 (x + 2) = 0

$\implies$ (7x - 1) (x + 2) = 0

$\implies$ 7x - 1 = 0 , x + 2 = 0

$\implies$ 7x = 1 , x = - 2

$\implies$ x = $\dfrac{1}{7}$ , x = - 2

$\mapsto$ Hence, the value of x = $\dfrac{1}{7}$ and - 2

Step-by-step explanation:

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