Question

Factorise and write down the factors of the expression :-
4a^3 + 12a^2 - 8a - 16

Plz answwr fast

Answer 1

Answer:

4a^3 + 12a^2 - 8a - 16

= ( 4a - 1 )² - 2 ( 4a - 1 )

= ( 4a - 1 ) [ 4a - 1 - 2 ]

= ( 4a - 1 ) ( 4a - 3 )

Therefore ,

( 4a - 1 ) and ( 4a - 3 ) are the factors .

Step-by-step explanation:

hope it's helpful

give thanks if it's helpful

Answer 2

$\: \huge{\underline{\mathfrak\red{❥answer❣}}}$

➭ 4a³ + 12a² - 8a - 16

➭ (4a-1)²-2 (4a-1)

➭ (4a-1) [4a-1 -2]

➭ (4a - 1) (4a - 3)

➭(4a-1) and (4a-3) are the factors

hope it was helpful to you