factorise ans show that 0
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p(x)=x^3-4x^2+x+6
if p(3)=0 then x-3is the factor of p(x).
x-3)x^3-4x^2+x+6(x^2-x-2
x^3-3x^2
- +
-x^2+x+6
-x^2+3x
+ -
-2x+6
-2x+6
+ -
0
for other two zeroes,
x^2-x-2=x^2-2x+x-2=x(x-2)+1(x-2)=(x+1)(x-2)
Hope it's helps u..
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