Factorise any of the following
Answers
Answer:
(i) 216 a³ -125
Ans) (6−5)(362+30+25)
(ii) 6x²-11x-35
Ans) (2−7)(3+5)
A) Factorise x³+6x²+11x+6 by long division method
Ans) Attachment above
Step-by-step explanation:
(i) Using Formula
(i) Using Formulaa³-b³= (a-b)(a²+ab+b²)
(i) Using Formulaa³-b³= (a-b)(a²+ab+b²)(6a)³-5³= (6a-5) {(6a)²+ 6a×5 + 5²}
(i) Using Formulaa³-b³= (a-b)(a²+ab+b²)(6a)³-5³= (6a-5) {(6a)²+ 6a×5 + 5²} = (6a-5) (36a²+ 30a+ 25)
(ii) Given : 6x²−11x−35
(ii) Given : 6x²−11x−35We can further write it as
(ii) Given : 6x²−11x−35We can further write it as 6x²−11x−35 = 6x²−21x+10x−35 [ splitting the middle term method ]
(ii) Given : 6x²−11x−35We can further write it as 6x²−11x−35 = 6x²−21x+10x−35 [ splitting the middle term method ]by taking out the common terms
(ii) Given : 6x²−11x−35We can further write it as 6x²−11x−35 = 6x²−21x+10x−35 [ splitting the middle term method ]by taking out the common terms6x²−11x−35 = 3x(2x−7)+5(2x−7)
(ii) Given : 6x²−11x−35We can further write it as 6x²−11x−35 = 6x²−21x+10x−35 [ splitting the middle term method ]by taking out the common terms6x²−11x−35 = 3x(2x−7)+5(2x−7)So we get,
(ii) Given : 6x²−11x−35We can further write it as 6x²−11x−35 = 6x²−21x+10x−35 [ splitting the middle term method ]by taking out the common terms6x²−11x−35 = 3x(2x−7)+5(2x−7)So we get,6x²−11x−35 = (3x+5)(2x−7)
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