Question

factorise ap^2-bq^2+bp^2-ap^2​

Answer 1

(ap^2 - ap^2) + ( bp^2 - bq^2)

b(p^2-q^2)
b(p+q) (p-q)

this is the ans......

Answer 2

Answer:

b(p-q)(p+q)

Step-by-step explanation:

ap²-bq²+bp²-ap²

= -bq²+bp² since the ap² terms cancel

= b(p²-q²)

= b(p-q)(p+q)