Question

-
Factorise
atb)cube - (a-b) cube both​

Answer 1

Answer:

Here's your answer

$(a + b) ^{3} - (a - b) ^{3} \\ \\ {a}^{3} + {b}^{3} + 3 {a}^{2} b + 3a {b}^{2} - ( {a}^{3} - \\ {b}^{3} - 3 {a}^{2} b + 3a {b}^{2} ) \\ \\ \\ = {a}^{3} + {b}^{3} + 3 {a}^{2} b + 3a {b}^{2} - {a}^{3} + {b}^{3} \\ + 3 {a}^{2} b - 3a {b}^{2}$

$</strong><strong>=</strong><strong>2 {b}^{3} + 6 {a}^{2} b$

=2 b(b^2 +3a^2)

Hope it helps ✌