Question

factorise (ax-1/5) ^2 - (x+1/3) ^2. Irrelevant answers will be reported. I want full explanation. ​

Answer 1

Step-by-step explanation:

Let (9x-1/5) = a

Let (9x-1/5) = aand (x+1/3) =b

Let (9x-1/5) = aand (x+1/3) =bthen

Let (9x-1/5) = aand (x+1/3) =bthena2 +b2=( a+b)(a+b)

Let (9x-1/5) = aand (x+1/3) =bthena2 +b2=( a+b)(a+b) put value of a and b

Let (9x-1/5) = aand (x+1/3) =bthena2 +b2=( a+b)(a+b) put value of a and b(9x-1/5 + x+1/3 ) (9x-1/5 + x+1/3)

Let (9x-1/5) = aand (x+1/3) =bthena2 +b2=( a+b)(a+b) put value of a and b(9x-1/5 + x+1/3 ) (9x-1/5 + x+1/3)(10x +2/15)(10x+2/15)

Answer 2

Step-by-step explanation:

pls thank my all answers of history