Math, asked by ryandias2412, 11 months ago

Factorise(ax+by) ^2 +(ay-bx) ^2


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Answers

Answered by TanujBoss
22

A pleasure afternoon to you dear friend,

( ax + by )² + (ay - bx )²

We know

(m+ n)² = m² + n² + 2mn

(m - n )² = m² + n² - 2mn

So ,

= [(ax)² + (by)² + 2(ax)(by)]+ [(ay²) + (bx)² + 2(ay)(bx)]

= [a²x² + b²y² + 2abxy][a²y² + b²x² - 2abxy]

= a²x² + b²y² + 2abxy + a²y² + b²x² -

2abxy

= a²x² + b²y² + a²y² + b²x²

= a² ( x² + y² ) + b² ( x² + y² )

= (a² + b² ) ( x² + y²)

Hope it helps

Please mark as the BRAINLLIEST


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Answered by aaryasudarshan
1

Answer:

hi i was looking for this question thank you so much for putting this up

Step-by-step explanation:

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