Factorise: (ax+by ) ² +(bx-ay)2
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Given : (ax+by)2+(bx−ay)2
By using the formula (a+b)2and(a−b)2'we get,
=a2x2+b2y2+2abxy+b2x2+a2y2−2abxy
=a2x2+b2y2+b2x2+a2y2
Rearranging the terms
=a2x2+b2x2+b2y2+a2y2
By taking the common terms out
=x2(a2+b2)+y2(a2+b2)
So we get,
(ax+by)2+(bx−ay)2= (a2+b
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