factorise-. axy+bcxy-az-bcz
Answers
Answered by
4
Answer:(xy-z) (a+bc)
Step-by-step explanation:
axy+bcxy-az-bcz
[By taking my and -z common]
= xy(a+bc)-z(a+bc)
= (xy-z) (a+bc)
Answered by
5
axy+bcxy-az-bcz
= xy(a+bc)-z(a+bc)
=(xy-z)(a+bc)
is the answer.
= xy(a+bc)-z(a+bc)
=(xy-z)(a+bc)
is the answer.
Similar questions