Question

factorise b^2-6b+9-c2​

Answer 1

By using identities

(a-b)=a-2ab+b?

and (a2-b2)=(a+b)(a-b)

4a?-b?+6b-9

4a²-(b?-6b+9)

(2a)2-(b2-(2)(3)(b)+33)

(2a)²-(6-3)2

(2a-(6-3)(2a+(b-3))

(2a-b+3)(2a+b-3)