Question

factorise: (b^2-c^2)+b(c^2-a^2)+c(a^2-b^2)

Answer 1

Answer:

a(b2+c2)+b(c2+a2)+c(a2+b2)+2abc

=ab2+ac2+bc2+ba2+ca2+cb2+2abc

=ba2+ca2+ab2+ac2+2abc+bc2+cb2

=a2(b+c)+a(b2+c2+2bc)+bc(c+b)

=a2(b+c)+(b+c)2+bc(b+c)

=(b+c)[(a2+a(b+c)+bc]

=(b+c)[a2+ab+ac+

Answer 2

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a(b² - c²) + b(c² - a²) + c(a² - b²)

→ ab² - ac² + bc² - ba² + ca² - cb²

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Hope it's helpful to you