Question

factorise (b+4)^2+4(b+4)-21 please help!!​

Answer 1

Answer:

answer for the given problem is given

Answer 2

Answer:

(b+1) (b+11)

Step-by-step explanation:

taking (b+4) = x

x^2 + 4x - 21

by splitting the middle term,

x^2 + 7x - 3x - 21

x(x + 7) -3(x + 7)

(x-3) (x+7)

(b+4-3) (b+4 +7)

(b+1) (b+11)

Hope this was helpful!