Question

Factorise b(c-d)^2+a(d-c)+3c-3d

Answer 1

Answer:

b(c-d)^2+a(d-c)+3c-3d

= b ( c - d ) ^2  - a ( c - d ) + 3 ( c - d )

= ( c - d ) { b ( c - d ) - a + 3 }

=( c - d ) { bc - bd - a + 3 } ( answer )

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Answer 2

Answer:

Here is the answer for your question

Step-by-step explanation:

b(c - d)^2 + a(d - c) + 3c - 3d

= b(c - d)^2  - a(c - d) + 3(c - d)

= (c - d) {b(c - d) - a + 3}

= (c - d) {bc - bd - a + 3}