Question

factorise b²c²(b²-c²)+c²a²(c²-a²)+b²a²(a²-b²)

Answer 1

b^4(c^2-a^2)+ c^4(a^2-b^2)+ a^4(b^2-c^2)

Answer 2

I'm not sure but it's answer is
$2 {a}^{2} + 2 {b }^{2} + 2 {c}^{2} + 2ab + 2bc + 2ca + {a}^{2} + {b }^{2} + {c}^{2}$