Question

Factorise bc(b - c) + ca(c - a) + ab(a - b).​

Answer 1

Answer:

Writing the question and breaking it in simpler form to make common to adjust the numbers easily.

1 + c + a + ca + b + bc + ab + abc

Taking (1 + c) common we get the first factor the question now move onto the next factors:

= 1(1+c) + a(1+c) + b(1+c) + ab(1+c)

After shifting the factors the other factor contains,

= (1+c)(1+a+b+ab)

Shifting the factor (1+ a + b + ab) and taking (1 + a) common we get,

= 1 (1+a) + b (1+a)

= (1+c) {1 (1+a) + b (1+a) }

After taking (1 + a) we get the factors as: (1+c) (1+a) (1+b)

Answer 2

Answer:

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