Question

factorise by alzebraic expressions x^8-y^8​

Answer 1

Answer:

X8-Y8

Step-by-step explanation:

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Answer 2

Answer:

using the identity

$(x + y)(x - y) = x {}^{2} - y {}^{2}$

factorising

$x {}^{8} - y {}^{8}$

$(x {}^{4} ) {}^{2} - (y {}^{4} ) {}^{2}$

$(x {}^{4} + y {}^{4} )(x {}^{4} - y {}^{4} )$

hence factorised