Question

FACTORISE BY BREAKING MIDDLE TERM:
6(a+b)2+5(a2-b2)-6(a-b)2 ​

Answer 1

Answer:

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Q. 1 P

4.0

( 11 Votes )

Let’s resolve int

Class 8th

West Bengal - Mathematics

13. Factorisation of Algebraic Expressions

Answer

6(a + b)2 + 5(a2-b2)-6(a-b)2

=6(a + b)2 + 5(a-b)(a + b)-6(a-b)2

=6(a + b)2 + 9(a-b)(a + b)-4(a-b)(a + b)-6(a-b)2

=3(a + b){2a + 2b + 3a-3b}-2(a-b){2a + 2b + 3a-3b}

=3(a + b)(5a-b)-2(a-b)(5a-b)

=(5a-b)(3a + 3b-2a + 3b)

=(5a-b)(a + 5b)

∴ the factors of 6(a + b)2 + 5(a2-b2)-6(a-b)2 are (5a-b)(a + 5b)